標題:
[10分]f.1 maths 方程式1題,,急急急急急
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發問:
1.) 2 [ p - 2 ( p + 1 ) ] - 1 = 8 p + 2 5 急急急急急!!!!!
最佳解答:
2[p-2(p+1)]-1=8p+25 2(p-2p-2)-1=8p+25 2(-p-2)-1=8p+25 -2p-4-1=8p+25 -2p-5=8p+25 10p=-30 p=-3
其他解答:
2[p-2(p+1)]-1=8p+25 2(p-2p-2)-1=8p+25 2(-p-2)-1=8p+25 -2p-4-1=8p+25 -2p-5=8p+25 10p=-30 p=-3|||||1) 2 [p - 2 ( p + 1 )] - 1 = 8p + 25 2(p - 2p - 2) - 1=8p + 25 2p - 4p - 4 - 1=8p + 25 -10p=30 p=-3|||||2 [ p - 2 ( p + 1 ) ] - 1 = 8 p + 2 5 2 (p- 2 p + 2 ) - 1 = 8 p + 2 5 2 p - 4 p + 4 - 1 = 8 p + 2 5 -8p -2p = 25 -4 -10p =21